According to Gilceane Cardozo, Medeiros, dos Santos Lacerda, Campos de Almeida, Pegas Henriques, Caroline Dani, Funchal (August 2013)They analyzed different chemical and physical properties and they found cultives of blueberrie fruit if they are grown. In organic and in conventional; Chlorogenic acid: 112.6 ± 1.1ab (organic), 68.4 ± 4.0a (conventional). Resveratrol: 2.9 ± 0.0a (organic), 2.4 ± 0.1b (conventional). Myricetin 3-arabinoside: 24.3 ± 0.2a (organic), 9.7 ± 0.5b (conventional), Quercetin 3-galactoside: 101.8 ± 7.9a (organic), 55.4 ± 2.4b (conventional). Quercetin 3-glucoside: 71.1 ± 7.1a (organic), 39.2 ± 5.0ab (conventional). Taking the given that the article gives us, N=5, therefore we can calculate the T the student of all the organic and conventional components.The T the Student of each component is; Chlorogenic acid: P=0,1464 (>0,005). Resveratrol: P=0.0011 (< 0,005). Myricetin 3-arabinoside: P=0.0001 (< 0,005). Quercetin 3-galactoside: P=0.0005 (< 0,005).Quercetin 3-glucoside: P=0.0063 (< 0,005).
If the scientists had attached the N, the Student's T could be calculated using this page: Graphpad
Gilceane Cardozo, Medeiros, dos Santos Lacerda, Campos de Almeida, Pegas Henriques, Caroline Dani, Funchal (August 2013)